Keep trying until you find the correct answer.

1. Consider the two loudspeakers in the diagram below. The loudspeakers, shown at t = 0, are playing sound of the same frequency. What is the phase difference, Δφ = 2π ^Δx/_λ , due to just the physical separation of the two speakers in the x direction?
   

   1.   ?    0
   2.   ?    ¹/₂π (90°)
   3.   ?    π (180°)
   4.   ?    ³/₂π (270°)
   5.   ?    2π (360°)

2. Consider the two loudspeakers in the diagram below. The loudspeakers, shown at t = 0, are playing sound of the same frequency. What is the phase difference, Δφ = 2π ^Δx/_λ , due to just the physical separation of the two speakers in the x direction?
   

   1.   ?    0
   2.   ?    ¹/₂π (90°)
   3.   ?    π (180°)
   4.   ?    ³/₂π (270°)
   5.   ?    2π (360°)

3. Consider the two loudspeakers in the diagram below. The loudspeakers, shown at t = 0, are playing sound of the same frequency. What is the phase difference, Δφ = 2π ^Δx/_λ , due to just the physical separation of the two speakers in the x direction?
   

   1.   ?    0
   2.   ?    ¹/₂π (90°)
   3.   ?    π (180°)
   4.   ?    ³/₂π (270°)
   5.   ?    2π (360°)

4. Consider the two loudspeakers in the diagram below. The loudspeakers, shown at t = 0, are playing sound of the same frequency. What is the phase difference, Δφ = 2π ^Δx/_λ , due to just the physical separation of the two speakers in the x direction?
   

   1.   ?    0
   2.   ?    ¹/₂π (90°)
   3.   ?    π (180°)
   4.   ?    ³/₂π (270°)
   5.   ?    2π (360°)

5. Consider the two loudspeakers in the diagram below. The loudspeakers, shown at t = 0, are playing sound of the same frequency. What is the phase difference, Δφ = 2π ^Δx/_λ , due to just the physical separation of the two speakers in the x direction?
   

   1.   ?    0
   2.   ?    ¹/₂π (90°)
   3.   ?    π (180°)
   4.   ?    ³/₂π (270°)
   5.   ?    2π (360°)

6. Consider the two loudspeakers in the diagram below. The loudspeakers, shown at t = 0, are playing sound of the same frequency. What is the phase difference, Δφ = 2π ^Δx/_λ , due to just the physical separation of the two speakers in the x direction?
   

   1.   ?    0
   2.   ?    ¹/₂π (90°)
   3.   ?    π (180°)
   4.   ?    ³/₂π (270°)
   5.   ?    2π (360°)

7. Consider the two loudspeakers in the diagram below. The loudspeakers, shown at t = 0, are playing sound of the same frequency. What is the phase difference, Δφ = 2π ^Δx/_λ , due to just the physical separation of the two speakers in the x direction?
   

   1.   ?    0
   2.   ?    ¹/₂π (90°)
   3.   ?    π (180°)
   4.   ?    ³/₂π (270°)
   5.   ?    2π (360°)

8. Consider the two loudspeakers in the diagram below. The loudspeakers, shown at t = 0, are playing sound of the same frequency. What is the phase difference, Δφ = 2π ^Δx/_λ , due to just the physical separation of the two speakers in the x direction?
   

   1.   ?    0
   2.   ?    ¹/₂π (90°)
   3.   ?    π (180°)
   4.   ?    ³/₂π (270°)
   5.   ?    2π (360°)

9. Consider the two loudspeakers in the diagram below. The loudspeakers, shown at t = 0, are playing sound of the same frequency. What is the phase difference, Δφ = 2π ^Δx/_λ , due to just the physical separation of the two speakers in the x direction?
   

   1.   ?    0
   2.   ?    ¹/₂π (90°)
   3.   ?    π (180°)
   4.   ?    ³/₂π (270°)
   5.   ?    2π (360°)

10. Consider the two loudspeakers in the diagram below. The loudspeakers, shown at t = 0, are playing sound of the same frequency. What is the phase difference, Δφ = 2π ^Δx/_λ , due to just the physical separation of the two speakers in the x direction?
    

    1.   ?    0
    2.   ?    ¹/₂π (90°)
    3.   ?    π (180°)
    4.   ?    ³/₂π (270°)
    5.   ?    2π (360°)

11. Consider the two loudspeakers in the diagram below. The loudspeakers, shown at t = 0, are playing sound of the same frequency. What is the phase difference, Δφ = 2π ^Δx/_λ , due to just the physical separation of the two speakers in the x direction?
    

    1.   ?    0
    2.   ?    ¹/₂π (90°)
    3.   ?    π (180°)
    4.   ?    ³/₂π (270°)
    5.   ?    2π (360°)

12. Consider the two loudspeakers in the diagram below. The loudspeakers, shown at t = 0, are playing sound of the same frequency. What is the phase difference, Δφ = 2π ^Δx/_λ , due to just the physical separation of the two speakers in the x direction?
    

    1.   ?    0
    2.   ?    ¹/₂π (90°)
    3.   ?    π (180°)
    4.   ?    ³/₂π (270°)
    5.   ?    2π (360°)

13. Consider the two loudspeakers in the diagram below. The loudspeakers, shown at t = 0, are playing sound of the same frequency. What is the phase difference, Δφ = 2π ^Δx/_λ , due to just the physical separation of the two speakers in the x direction?
    

    1.   ?    0
    2.   ?    ¹/₂π (90°)
    3.   ?    π (180°)
    4.   ?    ³/₂π (270°)
    5.   ?    2π (360°)

14. Consider the two loudspeakers in the diagram below. The loudspeakers, shown at t = 0, are playing sound of the same frequency. What is the phase difference, Δφ = 2π ^Δx/_λ , due to just the physical separation of the two speakers in the x direction?
    

    1.   ?    0
    2.   ?    ¹/₂π (90°)
    3.   ?    π (180°)
    4.   ?    ³/₂π (270°)
    5.   ?    2π (360°)

15. Consider the two loudspeakers in the diagram below. The loudspeakers, shown at t = 0, are playing sound of the same frequency. What is the phase difference, Δφ = 2π ^Δx/_λ , due to just the physical separation of the two speakers in the x direction?
    

    1.   ?    0
    2.   ?    ¹/₂π (90°)
    3.   ?    π (180°)
    4.   ?    ³/₂π (270°)
    5.   ?    2π (360°)

16. Consider the two loudspeakers in the diagram below. The loudspeakers, shown at t = 0, are playing sound of the same frequency. What is the phase difference, Δφ = 2π ^Δx/_λ , due to just the physical separation of the two speakers in the x direction?
    

    1.   ?    0
    2.   ?    ¹/₂π (90°)
    3.   ?    π (180°)
    4.   ?    ³/₂π (270°)
    5.   ?    2π (360°)

17. Consider the two loudspeakers in the diagram below. The loudspeakers, shown at t = 0, are playing sound of the same frequency. What is the phase difference, Δφ = 2π ^x/_λ , due to just the physical separation of the two speakers in the x direction?
    

    1.   ?    0
    2.   ?    ¹/₂π (90°)
    3.   ?    π (180°)
    4.   ?    ³/₂π (270°)
    5.   ?    2π (360°)

18. Consider the two loudspeakers in the diagram below. The loudspeakers, shown at t = 0, are playing sound of the same frequency. What is the phase difference, Δφ = 2π ^x/_λ , due to just the physical separation of the two speakers in the x direction?
    

    1.   ?    0
    2.   ?    ¹/₂π (90°)
    3.   ?    π (180°)
    4.   ?    ³/₂π (270°)
    5.   ?    2π (360°)

19. Consider the two loudspeakers in the diagram below. The loudspeakers, shown at t = 0, are playing sound of the same frequency. What is the phase difference, Δφ = 2π ^x/_λ , due to just the physical separation of the two speakers in the x direction?
    

    1.   ?    0
    2.   ?    ¹/₂π (90°)
    3.   ?    π (180°)
    4.   ?    ³/₂π (270°)
    5.   ?    2π (360°)

20. Consider the two loudspeakers in the diagram below. The loudspeakers, shown at t = 0, are playing sound of the same frequency. What is the phase difference, Δφ = 2π ^x/_λ , due to just the physical separation of the two speakers in the x direction?
    

    1.   ?    0
    2.   ?    ¹/₂π (90°)
    3.   ?    π (180°)
    4.   ?    ³/₂π (270°)
    5.   ?    2π (360°)

21. Consider the two loudspeakers in the diagram below. The loudspeakers, shown at t = 0, are playing sound of the same frequency. What is the phase difference, Δφ = 2π ^x/_λ , due to just the physical separation of the two speakers in the x direction?
    

    1.   ?    0
    2.   ?    ¹/₂π (90°)
    3.   ?    π (180°)
    4.   ?    ³/₂π (270°)
    5.   ?    2π (360°)

22. Consider the two loudspeakers in the diagram below. The loudspeakers, shown at t = 0, are playing sound of the same frequency. What is the phase difference, Δφ = 2π ^x/_λ , due to just the physical separation of the two speakers in the x direction?
    

    1.   ?    0
    2.   ?    ¹/₂π (90°)
    3.   ?    π (180°)
    4.   ?    ³/₂π (270°)
    5.   ?    2π (360°)

23. Consider the two loudspeakers in the diagram below. The loudspeakers, shown at t = 0, are playing sound of the same frequency. What is the phase difference, Δφ = 2π ^x/_λ , due to just the physical separation of the two speakers in the x direction?
    

    1.   ?    0
    2.   ?    ¹/₂π (90°)
    3.   ?    π (180°)
    4.   ?    ³/₂π (270°)
    5.   ?    2π (360°)

24. Consider the two loudspeakers in the diagram below. The loudspeakers, shown at t = 0, are playing sound of the same frequency. What is the phase difference, Δφ = 2π ^x/_λ , due to just the physical separation of the two speakers in the x direction?
    

    1.   ?    0
    2.   ?    ¹/₂π (90°)
    3.   ?    π (180°)
    4.   ?    ³/₂π (270°)
    5.   ?    2π (360°)

25. Consider the two loudspeakers in the diagram below. The loudspeakers, shown at t = 0, are playing sound of the same frequency. What is the phase difference, Δφ = 2π ^x/_λ , due to just the physical separation of the two speakers in the x direction?
    

    1.   ?    0
    2.   ?    ¹/₂π (90°)
    3.   ?    π (180°)
    4.   ?    ³/₂π (270°)
    5.   ?    2π (360°)

26. Consider the two loudspeakers in the diagram below. The loudspeakers, shown at t = 0, are playing sound of the same frequency. What is the phase difference, Δφ = 2π ^x/_λ , due to just the physical separation of the two speakers in the x direction?
    

    1.   ?    0
    2.   ?    ¹/₂π (90°)
    3.   ?    π (180°)
    4.   ?    ³/₂π (270°)
    5.   ?    2π (360°)

27. Consider the two loudspeakers in the diagram below. The loudspeakers, shown at t = 0, are playing sound of the same frequency. What is the phase difference, Δφ = 2π ^x/_λ , due to just the physical separation of the two speakers in the x direction?
    

    1.   ?    0
    2.   ?    ¹/₂π (90°)
    3.   ?    π (180°)
    4.   ?    ³/₂π (270°)
    5.   ?    2π (360°)

28. Consider the two loudspeakers in the diagram below. The loudspeakers, shown at t = 0, are playing sound of the same frequency. What is the phase difference, Δφ = 2π ^x/_λ , due to just the physical separation of the two speakers in the x direction?
    

    1.   ?    0
    2.   ?    ¹/₂π (90°)
    3.   ?    π (180°)
    4.   ?    ³/₂π (270°)
    5.   ?    2π (360°)

29. Consider the two loudspeakers in the diagram below. The loudspeakers, shown at t = 0, are playing sound of the same frequency. What is the phase difference, Δφ = 2π ^x/_λ , due to just the physical separation of the two speakers in the x direction?
    

    1.   ?    0
    2.   ?    ¹/₂π (90°)
    3.   ?    π (180°)
    4.   ?    ³/₂π (270°)
    5.   ?    2π (360°)

30. Consider the two loudspeakers in the diagram below. The loudspeakers, shown at t = 0, are playing sound of the same frequency. What is the phase difference, Δφ = 2π ^x/_λ , due to just the physical separation of the two speakers in the x direction?
    

    1.   ?    0
    2.   ?    ¹/₂π (90°)
    3.   ?    π (180°)
    4.   ?    ³/₂π (270°)
    5.   ?    2π (360°)

31. Consider the two loudspeakers in the diagram below. The loudspeakers, shown at t = 0, are playing sound of the same frequency. What is the phase difference, Δφ = 2π ^x/_λ , due to just the physical separation of the two speakers in the x direction?
    

    1.   ?    0
    2.   ?    ¹/₂π (90°)
    3.   ?    π (180°)
    4.   ?    ³/₂π (270°)
    5.   ?    2π (360°)

32. Consider the two loudspeakers in the diagram below. The loudspeakers, shown at t = 0, are playing sound of the same frequency. What is the phase difference, Δφ = 2π ^x/_λ , due to just the physical separation of the two speakers in the x direction?
    

    1.   ?    0
    2.   ?    ¹/₂π (90°)
    3.   ?    π (180°)
    4.   ?    ³/₂π (270°)
    5.   ?    2π (360°)

33. Consider the two loudspeakers in the diagram below. The loudspeakers, shown at t = 0, are playing sound of the same frequency. What is the phase difference, Δφ = 2π ^x/_λ , due to just the physical separation of the two speakers in the x direction?
    

    1.   ?    0
    2.   ?    ¹/₂π (90°)
    3.   ?    π (180°)
    4.   ?    ³/₂π (270°)
    5.   ?    2π (360°)

34. Consider the two loudspeakers in the diagram below. The loudspeakers, shown at t = 0, are playing sound of the same frequency. What is the phase difference, Δφ = 2π ^x/_λ , due to just the physical separation of the two speakers in the x direction?
    

    1.   ?    0
    2.   ?    ¹/₂π (90°)
    3.   ?    π (180°)
    4.   ?    ³/₂π (270°)
    5.   ?    2π (360°)

35. Consider the two loudspeakers in the diagram below. The loudspeakers, shown at t = 0, are playing sound of the same frequency. What is the phase difference, Δφ = 2π ^x/_λ , due to just the physical separation of the two speakers in the x direction?
    

    1.   ?    0
    2.   ?    ¹/₂π (90°)
    3.   ?    π (180°)
    4.   ?    ³/₂π (270°)
    5.   ?    2π (360°)

36. Consider the two loudspeakers in the diagram below. The loudspeakers, shown at t = 0, are playing sound of the same frequency. What is the phase difference, Δφ = 2π ^x/_λ , due to just the physical separation of the two speakers in the x direction?
    

    1.   ?    0
    2.   ?    ¹/₂π (90°)
    3.   ?    π (180°)
    4.   ?    ³/₂π (270°)
    5.   ?    2π (360°)

37. Consider the two loudspeakers in the diagram below. The loudspeakers, shown at t = 0, are playing sound of the same frequency. What is the phase difference, Δφ = 2π ^x/_λ , due to just the physical separation of the two speakers in the x direction?
    

    1.   ?    0
    2.   ?    ¹/₂π (90°)
    3.   ?    π (180°)
    4.   ?    ³/₂π (270°)
    5.   ?    2π (360°)

38. Consider the two loudspeakers in the diagram below. The loudspeakers, shown at t = 0, are playing sound of the same frequency. What is the phase difference, Δφ = 2π ^x/_λ , due to just the physical separation of the two speakers in the x direction?
    

    1.   ?    0
    2.   ?    ¹/₂π (90°)
    3.   ?    π (180°)
    4.   ?    ³/₂π (270°)
    5.   ?    2π (360°)

39. Consider the two loudspeakers in the diagram below. The loudspeakers, shown at t = 0, are playing sound of the same frequency. What is the phase difference, Δφ = 2π ^x/_λ , due to just the physical separation of the two speakers in the x direction?
    

    1.   ?    0
    2.   ?    ¹/₂π (90°)
    3.   ?    π (180°)
    4.   ?    ³/₂π (270°)
    5.   ?    2π (360°)

40. Consider the two loudspeakers in the diagram below. The loudspeakers, shown at t = 0, are playing sound of the same frequency. What is the phase difference, Δφ = 2π ^x/_λ , due to just the physical separation of the two speakers in the x direction?
    

    1.   ?    0
    2.   ?    ¹/₂π (90°)
    3.   ?    π (180°)
    4.   ?    ³/₂π (270°)
    5.   ?    2π (360°)

41. Consider the two loudspeakers in the diagram below. The loudspeakers, shown at t = 0, are playing sound of the same frequency. What is the phase difference, Δφ = 2π ^x/_λ , due to just the physical separation of the two speakers in the x direction?
    

    1.   ?    0
    2.   ?    ¹/₂π (90°)
    3.   ?    π (180°)
    4.   ?    ³/₂π (270°)
    5.   ?    2π (360°)

42. Consider the two loudspeakers in the diagram below. The loudspeakers, shown at t = 0, are playing sound of the same frequency. What is the phase difference, Δφ = 2π ^x/_λ , due to just the physical separation of the two speakers in the x direction?
    

    1.   ?    0
    2.   ?    ¹/₂π (90°)
    3.   ?    π (180°)
    4.   ?    ³/₂π (270°)
    5.   ?    2π (360°)

43. Consider the two loudspeakers in the diagram below. The loudspeakers, shown at t = 0, are playing sound of the same frequency. What is the phase difference, Δφ = 2π ^x/_λ , due to just the physical separation of the two speakers in the x direction?
    

    1.   ?    0
    2.   ?    ¹/₂π (90°)
    3.   ?    π (180°)
    4.   ?    ³/₂π (270°)
    5.   ?    2π (360°)

44. Consider the two loudspeakers in the diagram below. The loudspeakers, shown at t = 0, are playing sound of the same frequency. What is the phase difference, Δφ = 2π ^x/_λ , due to just the physical separation of the two speakers in the x direction?
    

    1.   ?    0
    2.   ?    ¹/₂π (90°)
    3.   ?    π (180°)
    4.   ?    ³/₂π (270°)
    5.   ?    2π (360°)

45. Consider the two loudspeakers in the diagram below. The loudspeakers, shown at t = 0, are playing sound of the same frequency. What is the phase difference, Δφ = 2π ^x/_λ , due to just the physical separation of the two speakers in the x direction?
    

    1.   ?    0
    2.   ?    ¹/₂π (90°)
    3.   ?    π (180°)
    4.   ?    ³/₂π (270°)
    5.   ?    2π (360°)

46. Consider the two loudspeakers in the diagram below. The loudspeakers, shown at t = 0, are playing sound of the same frequency. What is the phase difference, Δφ = 2π ^x/_λ , due to just the physical separation of the two speakers in the x direction?
    

    1.   ?    0
    2.   ?    ¹/₂π (90°)
    3.   ?    π (180°)
    4.   ?    ³/₂π (270°)
    5.   ?    2π (360°)

47. Consider the two loudspeakers in the diagram below. The loudspeakers, shown at t = 0, are playing sound of the same frequency. What is the phase difference, Δφ = 2π ^x/_λ , due to just the physical separation of the two speakers in the x direction?
    

    1.   ?    0
    2.   ?    ¹/₂π (90°)
    3.   ?    π (180°)
    4.   ?    ³/₂π (270°)
    5.   ?    2π (360°)

48. Consider the two loudspeakers in the diagram below. The loudspeakers, shown at t = 0, are playing sound of the same frequency. What is the phase difference, Δφ = 2π ^x/_λ , due to just the physical separation of the two speakers in the x direction?
    

    1.   ?    0
    2.   ?    ¹/₂π (90°)
    3.   ?    π (180°)
    4.   ?    ³/₂π (270°)
    5.   ?    2π (360°)

49. Consider the two loudspeakers in the diagram below. The loudspeakers, shown at t = 0, are playing sound of the same frequency. What is the phase difference, Δφ = 2π ^x/_λ , due to just the physical separation of the two speakers in the x direction?
    

    1.   ?    0
    2.   ?    ¹/₂π (90°)
    3.   ?    π (180°)
    4.   ?    ³/₂π (270°)
    5.   ?    2π (360°)

50. Consider the two loudspeakers in the diagram below. The loudspeakers, shown at t = 0, are playing sound of the same frequency. What is the phase difference, Δφ = 2π ^x/_λ , due to just the physical separation of the two speakers in the x direction?
    

    1.   ?    0
    2.   ?    ¹/₂π (90°)
    3.   ?    π (180°)
    4.   ?    ³/₂π (270°)
    5.   ?    2π (360°)

51. Consider the two loudspeakers in the diagram below. The loudspeakers, shown at t = 0, are playing sound of the same frequency. What is the phase difference, Δφ = 2π ^x/_λ , due to just the physical separation of the two speakers in the x direction?
    

    1.   ?    0
    2.   ?    ¹/₂π (90°)
    3.   ?    π (180°)
    4.   ?    ³/₂π (270°)
    5.   ?    2π (360°)

52. Consider the two loudspeakers in the diagram below. The loudspeakers, shown at t = 0, are playing sound of the same frequency. What is the phase difference, Δφ = 2π ^x/_λ , due to just the physical separation of the two speakers in the x direction?
    

    1.   ?    0
    2.   ?    ¹/₂π (90°)
    3.   ?    π (180°)
    4.   ?    ³/₂π (270°)
    5.   ?    2π (360°)

53. Consider the two loudspeakers in the diagram below. The loudspeakers, shown at t = 0, are playing sound of the same frequency. What is the phase difference, Δφ = 2π ^x/_λ , due to just the physical separation of the two speakers in the x direction?
    

    1.   ?    0
    2.   ?    ¹/₂π (90°)
    3.   ?    π (180°)
    4.   ?    ³/₂π (270°)
    5.   ?    2π (360°)

54. Consider the two loudspeakers in the diagram below. The loudspeakers, shown at t = 0, are playing sound of the same frequency. What is the phase difference, Δφ = 2π ^x/_λ , due to just the physical separation of the two speakers in the x direction?
    

    1.   ?    0
    2.   ?    ¹/₂π (90°)
    3.   ?    π (180°)
    4.   ?    ³/₂π (270°)
    5.   ?    2π (360°)

55. Consider the two loudspeakers in the diagram below. The loudspeakers, shown at t = 0, are playing sound of the same frequency. What is the phase difference, Δφ = 2π ^x/_λ , due to just the physical separation of the two speakers in the x direction?
    

    1.   ?    0
    2.   ?    ¹/₂π (90°)
    3.   ?    π (180°)
    4.   ?    ³/₂π (270°)
    5.   ?    2π (360°)

56. Consider the two loudspeakers in the diagram below. The loudspeakers, shown at t = 0, are playing sound of the same frequency. What is the phase difference, Δφ = 2π ^x/_λ , due to just the physical separation of the two speakers in the x direction?
    

    1.   ?    0
    2.   ?    ¹/₂π (90°)
    3.   ?    π (180°)
    4.   ?    ³/₂π (270°)
    5.   ?    2π (360°)

57. Consider the two loudspeakers in the diagram below. The loudspeakers, shown at t = 0, are playing sound of the same frequency. What is the phase difference, Δφ = 2π ^x/_λ , due to just the physical separation of the two speakers in the x direction?
    

    1.   ?    0
    2.   ?    ¹/₂π (90°)
    3.   ?    π (180°)
    4.   ?    ³/₂π (270°)
    5.   ?    2π (360°)

58. Consider the two loudspeakers in the diagram below. The loudspeakers, shown at t = 0, are playing sound of the same frequency. What is the phase difference, Δφ = 2π ^x/_λ , due to just the physical separation of the two speakers in the x direction?
    

    1.   ?    0
    2.   ?    ¹/₂π (90°)
    3.   ?    π (180°)
    4.   ?    ³/₂π (270°)
    5.   ?    2π (360°)

59. Consider the two loudspeakers in the diagram below. The loudspeakers, shown at t = 0, are playing sound of the same frequency. What is the phase difference, Δφ = 2π ^x/_λ , due to just the physical separation of the two speakers in the x direction?
    

    1.   ?    0
    2.   ?    ¹/₂π (90°)
    3.   ?    π (180°)
    4.   ?    ³/₂π (270°)
    5.   ?    2π (360°)

60. Consider the two loudspeakers in the diagram below. The loudspeakers, shown at t = 0, are playing sound of the same frequency. What is the phase difference, Δφ = 2π ^x/_λ , due to just the physical separation of the two speakers in the x direction?
    

    1.   ?    0
    2.   ?    ¹/₂π (90°)
    3.   ?    π (180°)
    4.   ?    ³/₂π (270°)
    5.   ?    2π (360°)

61. Consider the two loudspeakers in the diagram below. The loudspeakers, shown at t = 0, are playing sound of the same frequency. What is the phase difference, Δφ = 2π ^x/_λ , due to just the physical separation of the two speakers in the x direction?
    

    1.   ?    0
    2.   ?    ¹/₂π (90°)
    3.   ?    π (180°)
    4.   ?    ³/₂π (270°)
    5.   ?    2π (360°)

62. Consider the two loudspeakers in the diagram below. The loudspeakers, shown at t = 0, are playing sound of the same frequency. What is the phase difference, Δφ = 2π ^x/_λ , due to just the physical separation of the two speakers in the x direction?
    

    1.   ?    0
    2.   ?    ¹/₂π (90°)
    3.   ?    π (180°)
    4.   ?    ³/₂π (270°)
    5.   ?    2π (360°)

63. Consider the two loudspeakers in the diagram below. The loudspeakers, shown at t = 0, are playing sound of the same frequency. What is the phase difference, Δφ = 2π ^x/_λ , due to just the physical separation of the two speakers in the x direction?
    

    1.   ?    0
    2.   ?    ¹/₂π (90°)
    3.   ?    π (180°)
    4.   ?    ³/₂π (270°)
    5.   ?    2π (360°)

64. Consider the two loudspeakers in the diagram below. The loudspeakers, shown at t = 0, are playing sound of the same frequency. What is the phase difference, Δφ = 2π ^x/_λ , due to just the physical separation of the two speakers in the x direction?
    

    1.   ?    0
    2.   ?    ¹/₂π (90°)
    3.   ?    π (180°)
    4.   ?    ³/₂π (270°)
    5.   ?    2π (360°)

65. Consider the two loudspeakers in the diagram below. The loudspeakers, shown at t = 0, are playing sound of the same frequency. What is the phase difference, Δφ = 2π ^Δx/_λ , due to just the physical separation of the two speakers in the x direction?
    

    1.   ?    0
    2.   ?    ¹/₂π (90°)
    3.   ?    π (180°)
    4.   ?    ³/₂π (270°)
    5.   ?    2π (360°)

66. Consider the two loudspeakers in the diagram below. The loudspeakers, shown at t = 0, are playing sound of the same frequency. What is the phase difference, Δφ = 2π ^Δx/_λ , due to just the physical separation of the two speakers in the x direction?
    

    1.   ?    0
    2.   ?    ¹/₂π (90°)
    3.   ?    π (180°)
    4.   ?    ³/₂π (270°)
    5.   ?    2π (360°)

67. Consider the two loudspeakers in the diagram below. The loudspeakers, shown at t = 0, are playing sound of the same frequency. What is the phase difference, Δφ = 2π ^Δx/_λ , due to just the physical separation of the two speakers in the x direction?
    

    1.   ?    0
    2.   ?    ¹/₂π (90°)
    3.   ?    π (180°)
    4.   ?    ³/₂π (270°)
    5.   ?    2π (360°)

68. Consider the two loudspeakers in the diagram below. The loudspeakers, shown at t = 0, are playing sound of the same frequency. What is the phase difference, Δφ = 2π ^Δx/_λ , due to just the physical separation of the two speakers in the x direction?
    

    1.   ?    0
    2.   ?    ¹/₂π (90°)
    3.   ?    π (180°)
    4.   ?    ³/₂π (270°)
    5.   ?    2π (360°)

69. Consider the two loudspeakers in the diagram below. The loudspeakers, shown at t = 0, are playing sound of the same frequency. What is the phase difference, Δφ = 2π ^Δx/_λ , due to just the physical separation of the two speakers in the x direction?
    

    1.   ?    0
    2.   ?    ¹/₂π (90°)
    3.   ?    π (180°)
    4.   ?    ³/₂π (270°)
    5.   ?    2π (360°)

70. Consider the two loudspeakers in the diagram below. The loudspeakers, shown at t = 0, are playing sound of the same frequency. What is the phase difference, Δφ = 2π ^Δx/_λ , due to just the physical separation of the two speakers in the x direction?
    

    1.   ?    0
    2.   ?    ¹/₂π (90°)
    3.   ?    π (180°)
    4.   ?    ³/₂π (270°)
    5.   ?    2π (360°)

71. Consider the two loudspeakers in the diagram below. The loudspeakers, shown at t = 0, are playing sound of the same frequency. What is the phase difference, Δφ = 2π ^Δx/_λ , due to just the physical separation of the two speakers in the x direction?
    

    1.   ?    0
    2.   ?    ¹/₂π (90°)
    3.   ?    π (180°)
    4.   ?    ³/₂π (270°)
    5.   ?    2π (360°)

72. Consider the two loudspeakers in the diagram below. The loudspeakers, shown at t = 0, are playing sound of the same frequency. What is the phase difference, Δφ = 2π ^Δx/_λ , due to just the physical separation of the two speakers in the x direction?
    

    1.   ?    0
    2.   ?    ¹/₂π (90°)
    3.   ?    π (180°)
    4.   ?    ³/₂π (270°)
    5.   ?    2π (360°)

73. Consider the two loudspeakers in the diagram below. The loudspeakers, shown at t = 0, are playing sound of the same frequency. What is the phase difference, Δφ = 2π ^Δx/_λ , due to just the physical separation of the two speakers in the x direction?
    

    1.   ?    0
    2.   ?    ¹/₂π (90°)
    3.   ?    π (180°)
    4.   ?    ³/₂π (270°)
    5.   ?    2π (360°)

74. Consider the two loudspeakers in the diagram below. The loudspeakers, shown at t = 0, are playing sound of the same frequency. What is the phase difference, Δφ = 2π ^Δx/_λ , due to just the physical separation of the two speakers in the x direction?
    

    1.   ?    0
    2.   ?    ¹/₂π (90°)
    3.   ?    π (180°)
    4.   ?    ³/₂π (270°)
    5.   ?    2π (360°)

75. Consider the two loudspeakers in the diagram below. The loudspeakers, shown at t = 0, are playing sound of the same frequency. What is the phase difference, Δφ = 2π ^Δx/_λ , due to just the physical separation of the two speakers in the x direction?
    

    1.   ?    0
    2.   ?    ¹/₂π (90°)
    3.   ?    π (180°)
    4.   ?    ³/₂π (270°)
    5.   ?    2π (360°)

76. Consider the two loudspeakers in the diagram below. The loudspeakers, shown at t = 0, are playing sound of the same frequency. What is the phase difference, Δφ = 2π ^Δx/_λ , due to just the physical separation of the two speakers in the x direction?
    

    1.   ?    0
    2.   ?    ¹/₂π (90°)
    3.   ?    π (180°)
    4.   ?    ³/₂π (270°)
    5.   ?    2π (360°)

77. Consider the two loudspeakers in the diagram below. The loudspeakers, shown at t = 0, are playing sound of the same frequency. What is the phase difference, Δφ = 2π ^Δx/_λ , due to just the physical separation of the two speakers in the x direction?
    

    1.   ?    0
    2.   ?    ¹/₂π (90°)
    3.   ?    π (180°)
    4.   ?    ³/₂π (270°)
    5.   ?    2π (360°)

78. Consider the two loudspeakers in the diagram below. The loudspeakers, shown at t = 0, are playing sound of the same frequency. What is the phase difference, Δφ = 2π ^Δx/_λ , due to just the physical separation of the two speakers in the x direction?
    

    1.   ?    0
    2.   ?    ¹/₂π (90°)
    3.   ?    π (180°)
    4.   ?    ³/₂π (270°)
    5.   ?    2π (360°)

79. Consider the two loudspeakers in the diagram below. The loudspeakers, shown at t = 0, are playing sound of the same frequency. What is the phase difference, Δφ = 2π ^Δx/_λ , due to just the physical separation of the two speakers in the x direction?
    

    1.   ?    0
    2.   ?    ¹/₂π (90°)
    3.   ?    π (180°)
    4.   ?    ³/₂π (270°)
    5.   ?    2π (360°)

80. Consider the two loudspeakers in the diagram below. The loudspeakers, shown at t = 0, are playing sound of the same frequency. What is the phase difference, Δφ = 2π ^Δx/_λ , due to just the physical separation of the two speakers in the x direction?
    

    1.   ?    0
    2.   ?    ¹/₂π (90°)
    3.   ?    π (180°)
    4.   ?    ³/₂π (270°)
    5.   ?    2π (360°)